MATH SOLVE

2 months ago

Q:
# please please please help with my math problem. Thanks :)

Accepted Solution

A:

Answer:[tex]\sqrt{51}/10[/tex]Step-by-step explanation:Given that:sinФ = 7/10Putting in Pythagoras theorem:(7/10)^2 + cos^2 Ф = 149/100 + cos^2 Ф = 1Subtracting 49/100 on both sides:cos^2 Ф = 1 - 49/100By taking LCM cos^2 Ф = (100 - 49)/100cos^2 Ф = 51/100Taking square root on both sides we get:cos Ф = [tex]\sqrt{51}[/tex]/100I hope it will help you!