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Please please please help with my math problem. Thanks :)
4 months ago
Q:
please please please help with my math problem. Thanks :)
Accepted Solution
A:
Answer:[tex]\sqrt{51}/10[/tex]Step-by-step explanation:Given that:sinФ = 7/10Putting in Pythagoras theorem:(7/10)^2 + cos^2 Ф = 149/100 + cos^2 Ф = 1Subtracting 49/100 on both sides:cos^2 Ф = 1 - 49/100By taking LCM cos^2 Ф = (100 - 49)/100cos^2 Ф = 51/100Taking square root on both sides we get:cos Ф = [tex]\sqrt{51}[/tex]/100I hope it will help you!