MATH SOLVE

2 months ago

Q:
# please help with my math problem! Thank you :)

Accepted Solution

A:

Answer:cos Ф = 11/12Step-by-step explanation:Given that:sinФ = [tex]\sqrt{23}/12[/tex]Putting in Pythagoras theorem:([tex]\sqrt{23}/12[/tex])^2 + cos^2 Ф = 123/144 + cos^2 Ф = 1Subtracting 23/144 on both sides:cos^2 Ф = 1 - 23/144By taking LCMcos^2 Ф = (144 - 23)/144cos^2 Ф = 121/144Taking square root on both sides we get:cos Ф = 11/12I hope it will help you!