MATH SOLVE

2 months ago

Q:
# Marissa wants to blend candyselling for $1.80 per pound withcandy costing $1.20 per poundto get a mixture that costs her$1.40 per pound to make. Shewants to make 90 pounds of thecandy blend. How many poundsof each type of candy should sheuse?Explain in a formula, not just the answer!!!

Accepted Solution

A:

Answer:30 lb of $1.80 candy60 lb of $1.20 candyStep-by-step explanation:It generally works well to let a variable represent the quantity of the most-expensive contributor. Here, we can let x represent pounds of $1.80 candy.Then 90-x will be pounds of $1.20 candy, and the total cost of the mix will be ... 1.80x + 1.20(90-x)We want that to be the same value as 90 pounds of $1.40 per pound mix, so the equation is ... 1.80x + 1.20(90 -x) = 1.40(90)This can be simplified and solved like any two-step linear equation. 0.60x + 108 = 126 . . . . . simplify 0.60x = 18 . . . . . . . . . . . .subtract 108 x = 30 . . . . . . . . . . . . . . . divide by 0.60. This is pounds of $1.80 candy 90-x = 60 . . . . . pounds of $1.20 candy30 pounds of candy priced at $1.80 per pound, and 60 pounds of candy priced at $1.20 per pound should be used to make a mix that costs $1.40 per pound.